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0=6x^2+24x
We move all terms to the left:
0-(6x^2+24x)=0
We add all the numbers together, and all the variables
-(6x^2+24x)=0
We get rid of parentheses
-6x^2-24x=0
a = -6; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-6)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-6}=\frac{48}{-12} =-4 $
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